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Revision as of 19:31, 8 June 2017

$ln(_{5}q_{0}^{adj})=ln(_{5}q_{0}^{base})-0.06*HealthExp\%$

Revision as of 19:31, 8 June 2017 (view source) EmoryFerguson (talk \| contribs) No edit summary ← Older edit		Revision as of 19:31, 8 June 2017 (view source) EmoryFerguson (talk \| contribs) No edit summary Newer edit →
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	<math>ln(_5q^{adj}_0)		<math>ln(_5q^{adj}_0)=ln(_5q^{base}_0)-0.06*HealthExp%</math>