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Revision as of 18:29, 10 June 2017

<math>P_3=1-\sum^2_{i=1^{P_i}}

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	<math>~~P_i~~=~~\frac{S_i}{~~1+\sum^2_{i=1^{~~S_i}~~}}		<math>P_3=1-\sum^2_{i=1^{P_i}}